How to Use MySQL DATE_SUB Function

This tutorial explains MySQL DATE_SUB function which subtracts a slice of time (in days/hours, e.g., 1 day or 10 days) from the given date. We’ll describe the complete date arithmetic of this method with the help of simple examples.

Let’s now go through each of the sections one by one.

MySQL DATE_SUB() Function

As stated initially, DATE_SUB() is a built-in MySQL function subtracting the specified number of days from a given date. So, let’s see the details and check out how to use it.

MySQL DATE_SUB() Syntax

Below is the signature of the MySQL DATE_SUB() method:

DATE_SUB(Given_date, INTERVAL expr unit);

Below are the descriptions of the parameters in the above function.

+-------------+-----------------------------------------+
| # Params    | # Description                           |
+-------------+-----------------------------------------+
| Given_date  | Date value of DATE or DATETIME type.    |
| expr        | String representing time interval value.|
+-------------+-----------------------------------------+

Let’s take an example demonstrating the DATE_SUB() function to deduct 2 days from the current date.

SELECT DATE_SUB(CURDATE(), INTERVAL 2 DAY) result;

In the above statement, we’ve called the MySQL CURDATE() function which returns the present-day date. Anyways, after executing this command, it gives the following output:

1 MySQL Workbench
2019-07-07

The current date was “2019-07-09” at the time of execution. Hence, after subtracting two days, the result came out as above.

After a look at the arguments, let’s check out what the DATE_SUB() function returns.

• The return value would also be a DATE when the input value was of the DATE type.
• It would return a DATETIME if the input had time in hours, minutes, and seconds.
• A string value is sent back in all other cases.

Below is an example that calls the DATE_SUB() function to subtract in terms of hours.

SELECT DATE_SUB(CURDATE(), INTERVAL 6 HOUR) result;

After executing the above MySQL command, the result comes as:

1 MySQL Workbench
2019-07-08 18:00:00

MySQL DATE_SUB() Examples

Let’s now unveil several examples addressing different situations.

Using MySQL DATE_SUB with -ve Interval

The second argument (expr) of the DATE_SUB() function can also have -ve interval values.

However, if we pass a negative interval, it will act like the DATE_ADD() function. You will get more clarity by seeing the below example.

SELECT DATE_SUB(CURDATE(), INTERVAL -2 day) result;

Since the current date was “2019-07-09” at the time of execution, so the above command added two days to the final result. Check the result/outcome below.

1 MySQL Workbench
2019-07-11

Also Read: MySQL ABS Function with Simple Examples

Call MySQL DATE_SUB for Invalid Date

It is a negative case when you pass an invalid, malformed, or NULL date value to the DATE_SUB(). This function responds to such inputs by returning a NULL.

SELECT DATE_SUB('2019-13-09', INTERVAL 2 day) result;

The date “2019-13-09” is an incorrect value as the month can’t go beyond 12. Hence, after executing the above command, the output will be:

1 MySQL Workbench
NULL

The MySQL system would also notice this operation and throw a warning. We can track the same by issuing the below command:

SHOW WARNINGS;

The result/output:

Warning 1292 Incorrect datetime value: '2019-13-09'

Now, let’s have one more example to observe the behavior of the MySQL DATE_SUB() function for a malformed date.

-- Input date is malformed
SELECT DATE_SUB('2019-07-09-2019', INTERVAL 2 day) result;
-- Input date is NULL
SELECT DATE_SUB(NULL, INTERVAL 2 day) result;

After running the above MySQL statements, you should see the following outcome:

1 MySQL Workbench
NULL
NULL

Also Read: MySQL FIND_IN_SET Function with Simple Examples

MySQL DATE_SUB for Auto Adjustment

The DATE_SUB() function automatically adjusts the output in the following situation:

• After subtracting the interval (MONTH, YEAR, or YEAR_MONTH), the result comes to a date that surpasses the maximum day of the new month.

In this scenario, the function normalizes the final date to the last day of the new month. You can observe yourself by running through the example below:

-- Passing '2019-07-31' as the edge date value
SELECT DATE_SUB('2019-07-31', INTERVAL 1 MONTH) result;

After execution, we get this:

1 MySQL Workbench
2019-06-30

In this example, we backtracked by 1 month from July 31st, 2019. Therefore, the output comes to be June 30th, 2019. The day was automatically normalized to June, 30th instead of July, 1st.

Before You Leave

We hope that after wrapping up this tutorial, you will feel comfortable using the MySQL DATE_SUB() function. However, you may practice more with examples to gain confidence.

Also, to learn SQL from scratch to depth, read our step-by-step MySQL tutorial.

Lastly, our site needs your support to remain free. Share this post on social media (Facebook/Twitter) if you gained some knowledge from this tutorial.

Enjoy testing,
TechBeamers.